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2y^2-5y-75=0
a = 2; b = -5; c = -75;
Δ = b2-4ac
Δ = -52-4·2·(-75)
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-25}{2*2}=\frac{-20}{4} =-5 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+25}{2*2}=\frac{30}{4} =7+1/2 $
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